x = 1 -1 1 -1 1 -1 1
means x(1) = 1 and x(2) = -1 and so on tell x(7)
M(k) = sigma{x(i).*x(i+k)+x(i).*x(i+k-1).*x(i+k+1)}
for i = 0 to 6 - k
initially it should b solver by taking k=0 then k=1 and so on to k=7.
like wise we get m(0) m (1) and so on till m (7)
can any one do this ??
plz
thnx in advance!!
i have already solved part of it
- clear;
close all;
x=[1 -1 1 -1 1 -1 1 zeros(1,8)];
fork=1:7;
for j=1:7;
for i=1:7;
r(j,i)=(x(1,i).*x(1,i+k))+(x(1,i).*x(1,i+k+1).*x(1,i+k-1));
end;
end;
z(k,:)=sum(r,2);
end;
y=z(:,1)
out put im getting is 5 -5 3 -3 1 -1 0
but actual out put i should get is 6 5 -5 3 -3 1 -1
first answer is missing and last extra 0 is coming
