Matlab Forum

x = 1 -1 1 -1 1 -1 1

means x(1) = 1 and x(2) = -1 and so on tell x(7)

M(k) = sigma{x(i).*x(i+k)+x(i).*x(i+k-1).*x(i+k+1)}

for i = 0 to 6 - k

initially it should b solver by taking k=0 then k=1 and so on to k=7.

like wise we get m(0) m (1) and so on till m (7)

can any one do this ??
plz
thnx in advance!!


i have already solved part of it

• clear;
  close all;
  x=[1 -1 1 -1 1 -1 1 zeros(1,8)];
  fork=1:7;
      for j=1:7;
          for i=1:7;
         r(j,i)=(x(1,i).*x(1,i+k))+(x(1,i).*x(1,i+k+1).*x(1,i+k-1));
          end;
      end;
      z(k,:)=sum(r,2);
  end;
  y=z(:,1)
  
  out put im getting is 5 -5 3 -3 1 -1 0
  
  but actual out put i should get is 6 5 -5 3 -3 1 -1
  
  first answer is missing and last extra 0 is coming